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C语言,求能够被N整除的正整数的个数有多少个.(不...

#include int main(void) { int n,i,k; printf("请输入一个数据:"); while(scanf("%d",&n)==1) { k=0; for(i=2;i

#include int main(){ int i,n; int sum=0; printf("请输入一个正整数n的值:"); scanf("%d",&n); for(i=1;i

//希望我的回答对你的学习有帮助#includeint main(){int i,m,n;scanf("%d%d",&m,&n);for(i=m;i

#include int main(int argc,char *argv[]){ int m,i,n,t,N; printf("Input N(int N>0)...\nN="); if(scanf("%d",&N)!=1 || N

#includeint main(){int n,y=1,i; scanf("%d",&n); for(i=5;i

#include void main() { int n,i; printf("请输入n的值:"); scanf("%d",&n); printf("1~n中不可被3整除的数为:\n"); for(i=1;i

#include void main(){int i,n,k=0;scanf("%d",&n);for(i=1;i

干什么搞得这么紧张啊? int c = 0,i; scanf("%d", &n); for(i=2;i

#include void main() { int i,n,s; s=0; scanf("%d",&n); for ( i=1;i

#include void main( ) { int n, i, num , max ; scanf("%d", &n); scanf("%d", &num); max=num; for(i = 1; i < n; i++) { scanf("%d", &num); if(max < num) max = num; } printf("%d\n", max); }

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